5x^2+100x-2525=0

Solution for 5x^2+100x-2525=0 equation:

5x^2+100x-2525=0

a = 5; b = 100; c = -2525;
Δ = b2-4ac
Δ = 1002-4·5·(-2525)
Δ = 60500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{60500}=\sqrt{12100*5}=\sqrt{12100}*\sqrt{5}=110\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-110\sqrt{5}}{2*5}=\frac{-100-110\sqrt{5}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+110\sqrt{5}}{2*5}=\frac{-100+110\sqrt{5}}{10}
$